The gravitational force between two objects is described by the following formula.

$F = G\cfrac{m_1 \times m_2}{d^2}$ where $F$ is the gravitational force, $G$ is the gravitational constant, $m_1$ and $m_2$ are the masses of the two objects, and $d$ is the distance between the items.

Assume that the two objects are $6$ meters apart at first. They are then moved $18$ meters apart. How much is the gravitational force reduced?

A. $\cfrac{1}{9}$

B. $\cfrac{1}{12}$

C. $\cfrac{1}{3}$

D. $\cfrac{1}{4}$

E. $\cfrac{1}{27}$

$F = G\cfrac{m_1 \times m_2}{d^2}$ where $F$ is the gravitational force, $G$ is the gravitational constant, $m_1$ and $m_2$ are the masses of the two objects, and $d$ is the distance between the items.

Assume that the two objects are $6$ meters apart at first. They are then moved $18$ meters apart. How much is the gravitational force reduced?

A. $\cfrac{1}{9}$

B. $\cfrac{1}{12}$

C. $\cfrac{1}{3}$

D. $\cfrac{1}{4}$

E. $\cfrac{1}{27}$

*No Solution Steps*