Which of the following is equivalent to $\cfrac{3{x^3} - 2x^2 + 4}{x-{3}}$ ?
A. $3x^2 + {7}x + {21} + \cfrac{67}{x-{3}}$
B. $3x^2 + {7}x + \cfrac{25}{x-{3}}$
C. $3x^2 - {11}x - {33} - \cfrac{103}{x-{3}}$
D. $3x^2 - {11}x - \cfrac{37}{x-{3}}$
E. $3x^2 - {11}x + {33} + \cfrac{37}{x-{3}}$
No Solution StepsA. $3x^2 + {7}x + {21} + \cfrac{67}{x-{3}}$
B. $3x^2 + {7}x + \cfrac{25}{x-{3}}$
C. $3x^2 - {11}x - {33} - \cfrac{103}{x-{3}}$
D. $3x^2 - {11}x - \cfrac{37}{x-{3}}$
E. $3x^2 - {11}x + {33} + \cfrac{37}{x-{3}}$
