Which of the following is equivalent to $\cfrac{3{x^3} - 2x^2 + 1}{x-{2}}$ ?
A. $3x^2 + {4}x + {8} + \cfrac{17}{x-{2}}$
B. $3x^2 + {4}x + \cfrac{9}{x-{2}}$
C. $3x^2 - {8}x - {16} - \cfrac{33}{x-{2}}$
D. $3x^2 - {8}x - \cfrac{17}{x-{2}}$
E. $3x^2 - {8}x + {16} + \cfrac{17}{x-{2}}$
No Solution StepsA. $3x^2 + {4}x + {8} + \cfrac{17}{x-{2}}$
B. $3x^2 + {4}x + \cfrac{9}{x-{2}}$
C. $3x^2 - {8}x - {16} - \cfrac{33}{x-{2}}$
D. $3x^2 - {8}x - \cfrac{17}{x-{2}}$
E. $3x^2 - {8}x + {16} + \cfrac{17}{x-{2}}$
