Which of the following is equivalent to $\cfrac{2{x^3} - 4x^2 + 3}{x-{4}}$ ?
A. $2x^2 + {4}x + {16} + \cfrac{67}{x-{4}}$
B. $2x^2 + {4}x + \cfrac{19}{x-{4}}$
C. $2x^2 - {12}x - {48} - \cfrac{195}{x-{4}}$
D. $2x^2 - {12}x - \cfrac{51}{x-{4}}$
E. $2x^2 - {12}x + {48} + \cfrac{51}{x-{4}}$
No Solution StepsA. $2x^2 + {4}x + {16} + \cfrac{67}{x-{4}}$
B. $2x^2 + {4}x + \cfrac{19}{x-{4}}$
C. $2x^2 - {12}x - {48} - \cfrac{195}{x-{4}}$
D. $2x^2 - {12}x - \cfrac{51}{x-{4}}$
E. $2x^2 - {12}x + {48} + \cfrac{51}{x-{4}}$
