Find the solution to the following system.
$ \left \{ \begin{array}{cc} {y}={4}{x}+{16}\\{4}{x}-{7}{y}={-40} \end{array} \right. $
A. ${x}={-3}, \;{y}={4}$
B. ${x}={4}, \;{y}={-3}$
C. ${x}={3}, \;{y}={4}$
D. ${x}={-3}, \;{y}={-4}$
E. ${x}={-4}, \;{y}={3}$
$ \left \{ \begin{array}{cc} {y}={4}{x}+{16}\\{4}{x}-{7}{y}={-40} \end{array} \right. $
A. ${x}={-3}, \;{y}={4}$
B. ${x}={4}, \;{y}={-3}$
C. ${x}={3}, \;{y}={4}$
D. ${x}={-3}, \;{y}={-4}$
E. ${x}={-4}, \;{y}={3}$
