Find the solution to the following system.

$ \left \{ \begin{array}{cc} {y}={4}{x}+{16}\\{4}{x}-{7}{y}={-40} \end{array} \right. $

A. ${x}={-3}, \;{y}={4}$

B. ${x}={4}, \;{y}={-3}$

C. ${x}={3}, \;{y}={4}$

D. ${x}={-3}, \;{y}={-4}$

E. ${x}={-4}, \;{y}={3}$

$ \left \{ \begin{array}{cc} {y}={4}{x}+{16}\\{4}{x}-{7}{y}={-40} \end{array} \right. $

A. ${x}={-3}, \;{y}={4}$

B. ${x}={4}, \;{y}={-3}$

C. ${x}={3}, \;{y}={4}$

D. ${x}={-3}, \;{y}={-4}$

E. ${x}={-4}, \;{y}={3}$