Find the solution to the following system.

$ \left \{ \begin{array}{cc} {y}={3}{x}+{15}\\{5}{x}-{7}{y}={-41} \end{array} \right. $

A. ${x}={-4}, \;{y}={3}$

B. ${x}={3}, \;{y}={-4}$

C. ${x}={4}, \;{y}={3}$

D. ${x}={-4}, \;{y}={-3}$

E. ${x}={-3}, \;{y}={4}$

$ \left \{ \begin{array}{cc} {y}={3}{x}+{15}\\{5}{x}-{7}{y}={-41} \end{array} \right. $

A. ${x}={-4}, \;{y}={3}$

B. ${x}={3}, \;{y}={-4}$

C. ${x}={4}, \;{y}={3}$

D. ${x}={-4}, \;{y}={-3}$

E. ${x}={-3}, \;{y}={4}$